How many moles are equivalent to #3.58 * 10^23# formula units of #ZnCl_2#?

1 Answer
anor277
Feb 2, 2016

Approx. 0.60 moles of #ZnCl_2#.

Explanation:

In one mole of #ZnCl_2# there are #6.022xx10^23# formula units; i.e. #6.022xx10^23# INDIVIDUAL zinc atoms, and #2xx6.022xx10^23# INDIVIDUAL chlorine atoms.

Now the mass of one mole of #ZnCl_2# is #136.32# #g#. What is the mass of #3.58xx10^23# formula units of #ZnCl_2#?

Related questions
See all questions in The Mole
Impact of this question
9481 views around the world
You can reuse this answer
Creative Commons License