# How many moles are equivalent to 71.1 grams of barium nitride?

Dec 2, 2017

$\text{71.1 g Ba"_3"N"_2}$ is equivalent to $\text{0.162 mol Ba"_3"N"_2}$.
First you need to know the molar mass of barium nitride, $\left(\text{Ba"_3"N"_2}\right)$, which is $\text{439.995 g/mol}$.
71.1color(red)cancel(color(black)("g Ba"_3"N"_2))xx(1"mol Ba"_3"N"_2)/(439.995color(red)cancel(color(black)("g Ba"_3"N"_2)))="0.162 mol Ba"_3"N"_2"