How many moles are equivalent to 71.1 grams of barium nitride?

1 Answer
Dec 2, 2017

Answer:

#"71.1 g Ba"_3"N"_2"# is equivalent to #"0.162 mol Ba"_3"N"_2"#.

Explanation:

First you need to know the molar mass of barium nitride, #("Ba"_3"N"_2")#, which is #"439.995 g/mol"#.
https://pubchem.ncbi.nlm.nih.gov/compound/15251597

Divide the given mass of barium nitride, by its molar mass. Since molar mass is a fraction, g/mol, I prefer to divide by multiplying by its reciprocal, mol/g.

#71.1color(red)cancel(color(black)("g Ba"_3"N"_2))xx(1"mol Ba"_3"N"_2)/(439.995color(red)cancel(color(black)("g Ba"_3"N"_2)))="0.162 mol Ba"_3"N"_2"#