# How many moles are in 15 grams of NaOH?

Sodium hydroxide has a mass of $40.00$ $g \cdot m o {l}^{-} 1$
So, if you have $15.00$ $g$, this represents a molar quantity of:
$\frac{15 \cdot \cancel{g}}{40.00 \cdot \cancel{g} \cdot m o {l}^{-} 1}$ $=$ ?? $\text{mol}$