How many moles are in 2.5 grams of KCN?

Approx. $0.04 \cdot m o l$ with respect to $K C \equiv N$
$\text{No. of moles}$ $=$ $\text{Mass of stuff"/"Molar mass of stuff}$
$=$ $\frac{2.5 \cdot g}{65.12 \cdot g \cdot m o {l}^{-} 1}$ $=$ ??*mol