How many moles are in #3.70 * 10^-1# g of boron?

1 Answer
Dec 20, 2015

Answer:

1 mol of boron has a mass of #10.81# #g#. To find the molar quantity divide the mass by the molar mass.

Explanation:

Molar quantity #=# #(3.70xx10^(-1)*cancelg)/(10.81*cancelg*mol^-1)# #=# #?? mol#. Note how this treatment is dimensionally consistent; I used #g# and #g*mol^-1# units, and I get an answer in #mol# as required #((mol^-1)^-1=mol)#.