How many moles are in 363.8 g of #Ba(OH)_2#?

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Answer 1 · 2015-11-30T23:47:36

#2.1"mol "Ba(OH)_2#

Determine the molar mass of the barium hydroxide.

#Ba=(137.327"g")/"mol"#

#O=(16"g")/"mol"#

#H=(1.008"g")/"mol"#

molar mass of #Ba(OH)_2=((137.327+2(16)+2(1.008))"g")/"mol"#

#=(171.343"g")/"mol"#

We know we have #363.8"g"#.

#(363.8"g")/(x" mol")=(171.343"g")/(1"mol")#

Solve to find that there are #2.1"mol "Ba(OH)_2#.