# How many moles are in 75.0 g of dinitrogen trioxide, N_2O_3?

Jun 14, 2018

$\approx 0.987$ moles

#### Explanation:

To find the number of moles when given the mass of the substance, we divide the mass of the sample by its molar mass.

So, we get:

${n}_{{N}_{2} {O}_{3}} = \left(75 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{g")/(76.01color(red)cancelcolor(black)"g""/mol}}}}\right)$

$\approx 0.987 \setminus \text{mol}$