How many moles are in 937 g Ca(C_2H_3O_2)_2?

1 Answer
Feb 18, 2016

About 6 mol.

Explanation:

Calcium acetate has a formula weight of 158.17 g*mol^-1. To get the the number of moles, in fact the NUMBER of calcium acetate formula units, we divide the given mass by the molar mass:

(937*cancelg)/(158.17*cancelg*mol^-1) = ??

Note that this answer is dimensionally consistent. We seek an answer in mol, and we get an answer in 1/(mol^-1)="moles" as required. Capisce?

What number of calcium acetate formula units does this molar quantity represent?