How many moles are in 937 g #Ca(C_2H_3O_2)_2#?

1 Answer
anor277
Feb 18, 2016

About #6# #mol#.

Explanation:

Calcium acetate has a formula weight of #158.17# #g*mol^-1#. To get the the number of moles, in fact the NUMBER of calcium acetate formula units, we divide the given mass by the molar mass:

#(937*cancelg)/(158.17*cancelg*mol^-1)# #=# #??#

Note that this answer is dimensionally consistent. We seek an answer in #mol#, and we get an answer in #1/(mol^-1)="moles"# as required. Capisce?

What number of calcium acetate formula units does this molar quantity represent?

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