# How many moles are in 937 g Ca(C_2H_3O_2)_2?

Feb 18, 2016

About $6$ $m o l$.

#### Explanation:

Calcium acetate has a formula weight of $158.17$ $g \cdot m o {l}^{-} 1$. To get the the number of moles, in fact the NUMBER of calcium acetate formula units, we divide the given mass by the molar mass:

$\frac{937 \cdot \cancel{g}}{158.17 \cdot \cancel{g} \cdot m o {l}^{-} 1}$ $=$ ??

Note that this answer is dimensionally consistent. We seek an answer in $m o l$, and we get an answer in $\frac{1}{m o {l}^{-} 1} = \text{moles}$ as required. Capisce?

What number of calcium acetate formula units does this molar quantity represent?