How many moles are in sodium chloride in 150 mL of a 2 mM NaCl solution?

1 Answer
Mar 25, 2017

Answer:

#"Concentration"="Moles of solute"/"Volume of solution"#. And here there are:
#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol# of solute.

Explanation:

#"Concentration"="Moles of solute"/"Volume of solution"#

And thus #"moles of solute"="volume"xx"concentration"#

And here, for this product we have:

#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol#.

(I have changed the volume from #mL# to #L#, and from #mmol# to #mol# simply by using the appropriate multiplier.