How many moles are present in 165 g of Manganese?

1 Answer
Jun 13, 2016

Answer:

Approx. #3*"moles"# of metal.

Explanation:

#"Number of Moles"# #=# #"Mass"/"Molar Mass"#

Here, #(165*g)/(54.94*g*mol^-1)# #~=# #3*mol# of manganese metal.

What is the number of manganese atoms present?