# How many moles are present in 32.5 g aluminum chloride?

Sep 28, 2016

$\text{Moles of aluminum chloride "=" approx. 0.250 moles}$

#### Explanation:

$\text{Moles}$ $=$ $\text{Mass of compound"/"Molar mass of compound}$

$=$ $\frac{32.5 \cdot g}{\left(26.98 + 3 \times 35.45\right) \cdot g \cdot m o {l}^{-} 1}$

$=$ $\frac{32.5 \cdot g}{133.33 \cdot g \cdot m o {l}^{-} 1}$ $=$ ??" moles".