How many moles are present in 32.5 g aluminum chloride?

1 Answer
anor277
Sep 28, 2016

#"Moles of aluminum chloride "=" approx. 0.250 moles"#

Explanation:

#"Moles"# #=# #"Mass of compound"/"Molar mass of compound"#

#=# #(32.5*g)/((26.98+3xx35.45)*g*mol^-1)#

#=# #(32.5*g)/(133.33*g*mol^-1)# #=# #??" moles"#.

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