How many moles are there in 45 g of Neon?

Apr 13, 2016

Approx. $\frac{11}{4}$ moles.

Explanation:

Neon, $Z = 18$, has an equivalent mass of $20.18$ $g \cdot m o {l}^{-} 1$.

To find the molar quantity, simply divide the mass by the equivalent mass:

$\frac{45 \cdot \cancel{g}}{20.18 \cdot \cancel{g} \cdot m o {l}^{-} 1}$ $=$ ?? $m o l$.

How many $N e$ atoms are in this quantity?