# How many moles are in 5.96 g KOH?

Approx. $\frac{1}{10} \text{ moles}$
Potassium hydroxide has a molar mass of $56.11$ $g \cdot m o {l}^{-} 1$.
$n$ = $\text{Mass"/"Molar mass}$ $=$ $\frac{5.96 \cdot \cancel{g}}{56.11 \cdot \cancel{g} \cdot m o {l}^{-} 1}$ $=$ ?? mol