# How many moles is in 79.3 g Cl_2?

Aug 13, 2018

A bit over one mole....

#### Explanation:

To find the molar quantity of a given material we take the quotient....

${n}_{\text{number of moles"="mass of stuff"/"molar mass of stuff}}$

$= \frac{79.3 \cdot g}{70.90 \cdot g \cdot m o {l}^{-} 1} = 1.12 \cdot m o l \cdot \text{chlorine molecules}$.

And we got a molar quantity of MOLECULES....

Note that we calculated a MOLAR quantity of molecules, NOT atoms. Chlorine, as are all the room temperature gases with any chemistry, is DIATOMIC...i.e. $C {l}_{2} , {O}_{2} , {F}_{2} , {N}_{2} , {H}_{2.} \ldots$

How many moles of chlorine ATOMS does we got?