How many moles of a gas will occupy 3.62 liters at STP?

1 Answer
Jan 8, 2016

Answer:

At #"STP"#, #"3.62 L"# of an ideal gas would contain #"82.2 moles"#.

Explanation:

We first need to define #"STP"#. The most current definition of #"STP"# for gases is #"273.15 K"# and #1xx10^5 "Pa"#.
http://goldbook.iupac.org/S05910.html

Most people use #"100 kPa"# to avoid having to work with scientific notation or dealing with all those zeroes. #1xx10^5 "Pa"##=##100"kPa"#

At #100"kPa"#, the molar volume of a gas is #"22.710981 mol/L"#.
http://jfi.uchicago.edu/~ntt/formula/node197.html
https://en.m.wikipedia.org/wiki/Molar_volume

To determine the moles of a gas, divide the given volume by the molar volume.

#3.62cancel"L"xx(22.710981"mol")/(1cancel"L")="82.2 L"#