# How many moles of a gas will occupy 3.62 liters at STP?

Jan 8, 2016

At $\text{STP}$, $\text{3.62 L}$ of an ideal gas would contain $\text{82.2 moles}$.

#### Explanation:

We first need to define $\text{STP}$. The most current definition of $\text{STP}$ for gases is $\text{273.15 K}$ and $1 \times {10}^{5} \text{Pa}$.
http://goldbook.iupac.org/S05910.html

Most people use $\text{100 kPa}$ to avoid having to work with scientific notation or dealing with all those zeroes. $1 \times {10}^{5} \text{Pa}$$=$$100 \text{kPa}$

At $100 \text{kPa}$, the molar volume of a gas is $\text{22.710981 mol/L}$.
http://jfi.uchicago.edu/~ntt/formula/node197.html
https://en.m.wikipedia.org/wiki/Molar_volume

To determine the moles of a gas, divide the given volume by the molar volume.

$3.62 \cancel{\text{L"xx(22.710981"mol")/(1cancel"L")="82.2 L}}$