# How many moles of a pure gas are in a 30 liter scuba canister if the temperature of the canister is 27°C and the pressure is 0.4 atmospheres?

Feb 24, 2017

$n = 0.487 \cdot m o l$
$n = \frac{P V}{R T} = \frac{0.4 \cdot \cancel{a t m} \times 30 \cdot \cancel{L}}{0.0821 \cdot \cancel{L} \cdot \cancel{a t m} \cdot \cancel{{K}^{-} 1} \cdot m o {l}^{-} 1 \times 300 \cdot \cancel{K}}$
$= 0.487 \cdot m o l$