# How many moles of Ag+ are present in 25 mL of a 0.75 molar AgNO_3 solution?

Nov 7, 2015

$c = \frac{n}{v}$
$\therefore n = c \times v$
$\therefore n A {g}^{+} = 0.75 \times \frac{25}{1000} = 0.019$