# How many moles of Ag contain 4.49 * 10^23 atoms Ag?

May 13, 2018

$1 \text{mol" = 6.02*10^23"units}$
$4.49 \cdot {10}^{23} \text{atoms" * "mol"/(6.02*10^23"atoms") approx 0.746"mol}$