# How many moles of aluminum do 4.20x10^24 aluminum atoms represent?

Sep 14, 2016

Approx. $7$ $m o l$

#### Explanation:

The $1$ $\text{mole}$ of aluminum atoms has a mass of $26.98 \cdot g$, and (by definition!), there are $6.022 \times {10}^{23}$ individual aluminum atoms. The mole is thus the link between the micro world of atoms and molecules, which we can't see, to the macro world of grams and kilograms, which we can weigh out on a laboratory bench.

So we calculate the quotient:

$\left(4.20 \times {10}^{24} \cdot \text{aluminum atoms")/(6.022xx10^23*"aluminum atoms} \cdot m o {l}^{-} 1\right)$

$=$ ??*mol

What is the mass of this quantity of aluminum?

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