Question

How many moles of aluminum ions are present in 0.44 moles of `Al_2(SO_4)_3`?

Answer 1

Surely there are `0.88*mol` of aluminum metal in this molar quantity of salt....

Explanation:

In ONE mole of aluminum sulfate there are TWO mole of aluminum metal precisely...i.e. there are `54*g` of aluminum metal per `342.15*g` of salt...

Here we specify a molar quantity of `0.44*mol` with respect to aluminum sulfate….i.e. a mass of `150.5*g`...and in this quantity there are TWO EQUIV aluminum….i.e. a mass of `2xx0.44*molxx27.0*g=23.8*g`...