# How many moles of aluminum ions are present in 0.44 moles of Al_2(SO_4)_3?

Surely there are $0.88 \cdot m o l$ of aluminum metal in this molar quantity of salt....
In ONE mole of aluminum sulfate there are TWO mole of aluminum metal precisely...i.e. there are $54 \cdot g$ of aluminum metal per $342.15 \cdot g$ of salt...
Here we specify a molar quantity of $0.44 \cdot m o l$ with respect to aluminum sulfate….i.e. a mass of $150.5 \cdot g$...and in this quantity there are TWO EQUIV aluminum….i.e. a mass of $2 \times 0.44 \cdot m o l \times 27.0 \cdot g = 23.8 \cdot g$...