How many moles of aluminum oxide are in 6.83 g #Al_2O_3#?

1 Answer
anor277
Jan 7, 2016

Approx. #0.07# moles.

Explanation:

Moles of #Al_2O_3# #=# #(6.83*cancel(g))/(101.96*cancelg*mol^-1)# #=# #??# #mol# #Al_2O_3#

Please note that the answer is consistent dimensionally. Setting up the problem like this gives an answer in #(mol^-1)^-1# #=# #"moles"# AS REQUIRED.

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