# How many moles of aluminum, sulfur, and oxygen atoms are there in 7.00 moles of aluminum sulfate, Al_2(SO_4)_3?

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Meave60 Share
Nov 12, 2015

$7.00$ moles of $\text{Al"_2("SO"_4)_3}$ contain $14.0$ mol Al atoms, $21.0$ mol S atoms, and $84.0$ mol O atoms.

#### Explanation:

In one mole of aluminum sulfate, $\text{Al"_2"(SO"_4")"_3}$, there are 2 moles Al atoms, 3 moles sulfur atoms, and 12 moles O atoms.

To determine the number of moles of atoms of each element in 7.00 moles of the compound, multiply the number of moles times 7.00.

$\text{Al} :$7.00cancel("mol Al"_2("SO"_4)_3)xx(2"mol Al atoms")/(1cancel("mol Al"_2("SO"_4)_3))="14.0 mol Al atoms"

$\text{S} :$7.00cancel("mol Al"_2("SO"_4)_3)xx(3"mol S atoms")/(1cancel("mol Al"_2("SO"_4)_3))="21.0 mol S atoms"

$\text{O} :$7.00cancel("mol Al"_2("SO"_4)_3)xx(12"mol O atoms")/(1cancel("mol Al"_2("SO"_4)_3))="84.0 mol O atoms"

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