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How many moles of aluminum, sulfur, and oxygen atoms are there in 7.00 moles of aluminum sulfate, #Al_2(SO_4)_3#?

1 Answer
Nov 12, 2015

Answer:

#7.00# moles of #"Al"_2("SO"_4)_3"# contain #14.0# mol Al atoms, #21.0# mol S atoms, and #84.0# mol O atoms.

Explanation:

In one mole of aluminum sulfate, #"Al"_2"(SO"_4")"_3"#, there are 2 moles Al atoms, 3 moles sulfur atoms, and 12 moles O atoms.

To determine the number of moles of atoms of each element in 7.00 moles of the compound, multiply the number of moles times 7.00.

#"Al":##7.00cancel("mol Al"_2("SO"_4)_3)xx(2"mol Al atoms")/(1cancel("mol Al"_2("SO"_4)_3))="14.0 mol Al atoms"#

#"S":##7.00cancel("mol Al"_2("SO"_4)_3)xx(3"mol S atoms")/(1cancel("mol Al"_2("SO"_4)_3))="21.0 mol S atoms"#

#"O":##7.00cancel("mol Al"_2("SO"_4)_3)xx(12"mol O atoms")/(1cancel("mol Al"_2("SO"_4)_3))="84.0 mol O atoms"#