How many moles of atoms are in 3.00 g of #""^13C#?

1 Answer
anor277
Jun 7, 2016

There are #3/13xxN_A" carbon atoms"#, where #N_A="Avogadro's Number, "6.022xx10^23*mol^-1#

Explanation:

In #13*g# of #""^(13)C# there are precisely #"Avogadro's number of atoms"#.You have specified #3.00*g#, thus there are #(3.00*g)/(13.00*g*mol)xx6.022xx10^23*mol^-1# #=# #??""^13C " atoms"#

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