# How many moles of boron are in 1.21*10^24 boron atoms?

Well, in $1$ $\text{mole}$ of boron there are $6.022 \times {10}^{23}$ boron atoms.
So, $\text{moles of boron}$ $=$ $\left(1.21 \times {10}^{24} \text{ boron atoms")/(6.022xx10^23" boron atoms} \cdot m o {l}^{-} 1\right)$
$=$ $\text{How many moles?}$ I count about 2. What is the mass of this molar quantity?