How many moles of #CoO(s)# will be formed for every mole of #CoCl_2 * 6H_2O(s)#?
The ratio is
Assuming you meant how many moles of
(The water was ignored because it's solvent, so, even if we do add it it's not gonna participate in the reaction)
Balancing that equation we see we need to have 2 sodiums in the LHS and 2 chlorides in the RHS, which we can solve by putting a 2 in front of
So we know that 1 mole of cobalt (II) chloride makes 1 mole of cobalt (II) hydroxide, next we need to see the dehydration reaction.
Which, if we check is already balanced, so we can say that 1 mole of cobalt (II) chloride makes 1 mole of cobalt (II) oxide.