How many moles of Cu are in #1.48*10^25# Cu atoms?

1 Answer
Meave60
Mar 30, 2018

There are #"24.6 mol Cu atoms"# in #1.48xx10^25# #"Cu atoms"#.

Explanation:

One mole of atoms contains #6.022xx10^23# atoms. You may recognize this as Avogadro's number #(N_"A")#. Divide the given number of atoms by #(6.022xx10^23"atoms")/"mol"#. Since #(6.022xx10^23"atoms")/"mol"# is a fraction, divide by multiplying by its reciprocal.

#1.48xx10^25color(red)cancel(color(black)("atoms Cu"))xx(1"mol Cu")/(6.022xx10^23color(red)cancel(color(black)("atoms Cu")))="24.6 mol Cu"# (rounded to three significant figures)

There are #"24.6 mol Cu atoms"# in #1.48xx10^25# #"Cu atoms"#.

Related questions
See all questions in The Mole
Impact of this question
27889 views around the world
You can reuse this answer
Creative Commons License