# How many moles of ethanol are represented by 50.0 kg of ethanol?

$1.09 \cdot {10}^{3} m o l$
${C}_{2} {H}_{5} O H$ is the formula for ethanol.
$50.0 k g \left(\frac{1000 g}{k g}\right) \left(\frac{{C}_{2} {H}_{5} O H}{46.08 g}\right) = 1.09 \cdot {10}^{3} m o l$