How many moles of gas are contained in .89 L at 21.0 oC and .987 atm pressure?

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Answer 1 · 2018-03-03T04:32:34

#0.03609mol#

We shall assume that this is an Ideal Gas, and can thus use the Ideal Gas Law:

#PV=nRT#

where #P=# Pressure (pascals)

where #V=# Volume (#m^3#)

where #n=# moles (mol)

where #T=# Temperature (Kelvin)

and #R# is the gas constant #8.31441 J K^-1 mol^-1#

Now, we convert the units:

#0.987atm=100007.775pa#

#0.89L=0.89dm^3=0.00089m^3#

#21^oC=294.15K#

Inputting the values into the equation:

#->100007.775 * 0.00089 = n * 8.31441 * 294.15#

#-> 89.0069=2445.6837n#

Solve for n:

#n= 89.0069/2445.6837#

#n=0.03639mol#

Thus, solved.