# How many moles of glucose are required to form 122 g of ethanol?

Nov 27, 2015

${C}_{6} {H}_{12} {O}_{6} \left(a q\right) \rightarrow 2 {C}_{2} {H}_{5} O H \left(a q\right) + 2 C {O}_{2} \left(g\right)$
Molecular mass of ethanol, $46.07$ $g \cdot m o {l}^{-} 1$.
We require, (122.0*g)/(46.07*g*mol^-1 $=$ $2.65$ $m o l$ ethanol.
Given that 1 mol of glucose gives 2 moles of ethyl alcohol upon fermentation, we need to ferment at least $1.33$ $m o l$ of sugar. What is this amount in grams?