# How many moles of H_2SO_4 are present in 0.500 L of a 0.150 M H_2SO_4 solution?

$0.075 m o l$
Numer of moles of ${H}_{2} S {O}_{4}$ are present in 0.500 L of a 0.150 M ${H}_{2} S {O}_{4}$ solution is
$= \text{concentration in molarity"xx "Volume in liter}$
$= 0.15 \frac{m o l}{L} \times 0.500 L = 0.075 m o l$