# How many moles of H_2SO_4 are present in 1.63 liters of a .954 M solution?

Apr 12, 2017

Here, there are $1.56 \cdot m o l$ with respect to ${H}_{2} S {O}_{4}$.........

#### Explanation:

By definition, $\text{Concentration"="Moles"/"Volume}$, and thus by manipulating this expression, we get, $\text{Volume"="Moles"/"Concentration}$, or, as we require here..............

$\text{Moles"="Volume"xx"Concentration}$; and so we calculate the product.........

$1.63 \cdot L \times 0.954 \cdot m o l \cdot {L}^{-} 1 = 1.63 \cdot \cancel{L} \times 0.954 \cdot m o l \cdot \cancel{{L}^{-} 1}$

$= 1.56 \cdot m o l$ of ${H}_{2} S {O}_{4}$.

Such a product is dimensionally consistent; we wanted an answer in moles and the product gave us one, which persuades us that we have done the right thing arithmetically.

What is the concentration with respect to ${H}^{+}$ or ${H}_{3} {O}^{+}$?