How many moles of #H_2SO_4# are present in 1.63 liters of a .954 M solution?

1 Answer
Apr 12, 2017

Answer:

Here, there are #1.56*mol# with respect to #H_2SO_4#.........

Explanation:

By definition, #"Concentration"="Moles"/"Volume"#, and thus by manipulating this expression, we get, #"Volume"="Moles"/"Concentration"#, or, as we require here..............

#"Moles"="Volume"xx"Concentration"#; and so we calculate the product.........

#1.63*Lxx0.954*mol*L^-1=1.63*cancelLxx0.954*mol*cancel(L^-1)#

#=1.56*mol# of #H_2SO_4#.

Such a product is dimensionally consistent; we wanted an answer in moles and the product gave us one, which persuades us that we have done the right thing arithmetically.

What is the concentration with respect to #H^+# or #H_3O^+#?