How many moles of #H_2SO_4# are present in half a liter of a 0.150 M #H_2SO_4# solution?

1 Answer
May 12, 2017

Answer:

#0.075*mol#

Explanation:

#"Molarity"="Moles of solute"/"Volume of solution"#

And thus, #"Moles of solute"="Volume of solution"xx"molarity"#

#=0.5*Lxx0.150*mol*L^-1=0.075*mol# with respect to #H_2SO_4#.

Of course, we speak of a formal concentration. We know that in aqueous solution sulfuric acid speciates to give #HSO_4^-# and #SO_4^(2-)#, and equivalent quantities of #H_3O^+#.