How many moles of H_2SO_4 are present in half a liter of a 0.150 M H_2SO_4 solution?

May 12, 2017

$0.075 \cdot m o l$

Explanation:

$\text{Molarity"="Moles of solute"/"Volume of solution}$

And thus, $\text{Moles of solute"="Volume of solution"xx"molarity}$

$= 0.5 \cdot L \times 0.150 \cdot m o l \cdot {L}^{-} 1 = 0.075 \cdot m o l$ with respect to ${H}_{2} S {O}_{4}$.

Of course, we speak of a formal concentration. We know that in aqueous solution sulfuric acid speciates to give $H S {O}_{4}^{-}$ and $S {O}_{4}^{2 -}$, and equivalent quantities of ${H}_{3} {O}^{+}$.