# How many moles of "H"_2"SO"_4 are present in "0.500 L" of a "0.150-M" "H"_2"SO"_4 solution?

##### 1 Answer
May 9, 2018

${\text{0.0750 moles H"_2"SO}}_{4}$

#### Explanation:

$\text{Molarity}$ $= \text{Moles"/"Liter}$

Using this, we can fill in several of these values since they are given. This gives us the equation:

$0.150 = \frac{\text{Moles}}{0.500}$

By multiplying both sides by $0.500$, we find

$\text{0.150 mol/L" * "0.500 L" = "Moles}$

or simplified

$\text{0.0750 mol = Moles}$