How many moles of #HCl# are present in 0.70 L of a 0.33 M #HCl# solution?

1 Answer
anor277
Jan 29, 2016

Approx. #0.23# #mol#

Explanation:

#"Concentration"# #=# #("amount of substance (moles)")/("volume of solution (L)")#

Thus #"amount of substance"#

#=# #"Concentration"xx"volume of solution"#

#=# #0.33*mol*cancel(L^-1) xx 0.70*cancelL# #=# #0.231# #mol# #HCl#

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