# How many moles of hydrogen will be needed to react with 2 moles of nitrogen in the reaction N_2 + H_2 -> NH_3?

Feb 28, 2016

The balanced equation for dinitrogen reduction is:
${N}_{2} \left(g\right) + 3 {H}_{2} \left(g\right) \rightarrow 2 N {H}_{3} \left(g\right)$.

$2$ $\text{moles}$ ${N}_{2}$ requires $6$ moles ${H}_{2}$.

#### Explanation:

The equation above represents probably the most important inorganic reaction on the planet in that it allows the formation of ammonia and nitrates for nitrogenous fertilizer.

Your question specified 2 moles of nitrogen. I would be quite justified in assuming that the questioner meant 2 moles of dinitrogen gas, i.e. the equivalent of $4$ moles of $\text{NITROGEN}$ atoms.

Thus, if $2$ moles of dinitrogen gas are specified, $6$ moles of dihydrogen gas are required.