Question

How many moles of ions are in 27.5 g of `MgCl_2`?

Answer 1

`MgCl_2(s) rarr Mg^(2+) +2Cl^-`

Explanation:

`"Moles of magnesium salt"` `=` `(27.5*g)/(95.21*g*mol^-1)` `=` `0.289*mol.`

There are thus `2xx0.289*mol` `"chloride ions"`, and `0.289*mol` `"magnesium ions"`, almost an entire mole of ions.