Question

How many moles of KCI are present in 189 mL of a 0.745 M solution?

Answer 1

Approx. `0.15*mol..........`

Explanation:

`"Concentration"="Moles of solute"/"Volume of solution"`

To get one quantity or the other, we take the quotient or the appropriate product.

Adn thus `"Moles of solute"="Concentration"xx"Volume of solution"`

`=0.745*mol*cancel(L^-1)xx189*cancel(mL)xx10^-3cancelL*cancel(mL^-1)=??*mol.`

And thus the calculation was dimensionally consistent.