# How many moles of KCI are present in 189 mL of a 0.745 M solution?

Nov 25, 2016

Approx. $0.15 \cdot m o l \ldots \ldots \ldots .$

#### Explanation:

$\text{Concentration"="Moles of solute"/"Volume of solution}$

To get one quantity or the other, we take the quotient or the appropriate product.

Adn thus $\text{Moles of solute"="Concentration"xx"Volume of solution}$

=0.745*mol*cancel(L^-1)xx189*cancel(mL)xx10^-3cancelL*cancel(mL^-1)=??*mol.

And thus the calculation was dimensionally consistent.