# How many moles of N are in 0.167 g of N_2O?

Mar 4, 2017

$\text{This is TWICE the molar quantity of nitrous oxide.........}$
$\text{Moles of}$ ${N}_{2} O$ $=$ $\frac{0.167 \cdot g}{44.01 \cdot g \cdot m o {l}^{-} 1} = 3.80 \times {10}^{-} 3 \cdot m o l$.
$\text{Moles of nitrogen atoms} = 2 \times 3.80 \times {10}^{-} 3 \cdot m o l = 7.60 \times {10}^{-} 3 \cdot m o l \ldots \ldots \ldots$