How many moles of #N# are in 0.193 g of #N_2O#?

1 Answer
anor277
Feb 22, 2017

There are #=8.77xx10^-3*mol" of nitrogen atoms.........."#

Explanation:

#"Moles of nitrous oxide"# #=# #(0.193*g)/(44.01*g*mol^-1)#

#=4.39xx10^-3*mol.#

And thus #"moles of nitrogen atoms"#

#=4.39xx10^-3*molxx2=??#

How can I convert this molar quantity into a number of nitrogen atoms?

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