# How many moles of N are in 0.193 g of N_2O?

Feb 22, 2017

There are $= 8.77 \times {10}^{-} 3 \cdot m o l \text{ of nitrogen atoms..........}$

#### Explanation:

$\text{Moles of nitrous oxide}$ $=$ $\frac{0.193 \cdot g}{44.01 \cdot g \cdot m o {l}^{-} 1}$

$= 4.39 \times {10}^{-} 3 \cdot m o l .$

And thus $\text{moles of nitrogen atoms}$

=4.39xx10^-3*molxx2=??

How can I convert this molar quantity into a number of nitrogen atoms?