How many moles of #Na^+# ions are in 150 mL of a 0.200 M #Na_3PO_4# solution?

1 Answer
Jun 2, 2018

Answer:

#"0.09 mol"#

Explanation:

Moles of #"Na"_3"PO"_4# in the solution is

#"n" =\ "Molarity × Volume"#

#color(white)("n") =\ "0.200 M × 0.150 L"#

#color(white)("n") =\ "0.03 mol"#

There are #3# atoms in each molecule of #"Na"_3"PO"_4#.

So, Moles of #"Na"^+# ions #"= 3 × 0.03 mol = 0.09 mol"#