# How many moles of Na^+ ions are in 150 mL of a 0.200 M Na_3PO_4 solution?

Jun 2, 2018

$\text{0.09 mol}$

#### Explanation:

Moles of ${\text{Na"_3"PO}}_{4}$ in the solution is

$\text{n" =\ "Molarity × Volume}$

color(white)("n") =\ "0.200 M × 0.150 L"

color(white)("n") =\ "0.03 mol"

There are $3$ atoms in each molecule of ${\text{Na"_3"PO}}_{4}$.

So, Moles of ${\text{Na}}^{+}$ ions $\text{= 3 × 0.03 mol = 0.09 mol}$