How many moles of NaCl are contained in 467 mL of a .244M solution of NaCl?
#color(blue)("molarity" = "moles of solute"/"liters of solution")#
Simply put, dissolving one mole of a solute in one liter of solution will produce a
In your case, the volume of the solution is said to be equal to
Since you have a little less than half of a liter, i.e.
More specifically, the solution will contain - do not forget to convert the volume of the solution from milliliters to liters!
#color(blue)(c = n/V implies n = c * V)#
#n = 0.244 "moles"/color(red)(cancel(color(black)("L"))) * 467 * 10^(-3) color(red)(cancel(color(black)("L"))) = "0.1139 moles NaCl"#
Rounded to three sig figs, the answer will be
#n_(NaCl) = color(green)("0.114 moles")#
SIDE NOTE Because sodium chloride dissociates completely in aqueous solution, you wouldn't actually say that you have a
Instead, you would say that you have a solution that is