# How many moles of NaCl are present in 20.0 g of NaCl?

$\text{0.342 mol}$
Molar mass of $\text{NaCl = 58.4 g/mol}$
Number of moles in $\text{20.0 g NaCl}$ is
(20.0 cancel"g")/(58.4 cancel"g""/mol") = "0.342 mol"