# How many moles of NaCl are present in 500 mL of a 1.55 NaCl solution?

Apr 13, 2017

Molarity= moles of solute/Liters of solution

$\text{1.55 M" = "moles"/".5}$

$\text{moles = 0.775 moles of NaCl}$

#### Explanation:

$\text{Molarity" = "moles of solute"/"Liters of solution}$

First, we need to convert $\text{500 mL}$ to Liters

$\text{500 ml" * "1 L"/"1000 ml" = ".5 L}$

Now we can plug into our formula

$\text{1.55M" = "moles"/".5}$

$\text{moles = 0.775 moles of NaCl}$