How many moles of NaCl will react completely with 18.5 L F2 gas at 300.0 K and 1.00 atm? 0.751 mol NaCl 1.33 mol NaCl 1.50 mol NaCl 2.66 mol NaCl

1 Answer
Jun 13, 2018

1.50 moles of NaCl.

Explanation:

This is our balanced single-substitution reaction:

2NaCl + F_2 -> 2NaF + Cl_2

From this, we can see that 1 mole of F_2 gas corresponds to 2 moles of NaCl.

To calculate the moles of NaCl needed to react with F_2 gas, we'll first need to find the number of moles of F_2.
This can be done using the Ideal Gas Law:

pV = nRT

Where p is pressure, V is volume, n is number of moles, R is the gas constant, and T is temperature.

We're already given volume, temperature, and pressure from the question, so we can just plug those values in and solve for n:

pV = nRT

n = (pV)/(RT) = ("1.00 atm" xx "18.5 L")/("0.08206 L atm/K mol" xx "300.0 K") = "0.751 mol"

Since 1 mole of F_2 gas corresponds to 2 moles of NaCl, "0.751" moles of F_2 gas will correspond to 2xx0.751 = 1.50 moles of NaCl.