How many moles of #NaOH# are present in 15.0 mL of 0.110 M #NaOH#?

1 Answer
Jun 5, 2016

Answer:

0.00165 moles of NaOH

Explanation:

Molarity is represented by the following equation:

http://formulas.tutorvista.com/chemistry/molarity-formula.html

In our case, we already have the molarity and the volume of solution. However, the volume does not have the proper units since it is given in terms of milliliters instead of liters. We can convert 15.0 mL into liters by using the conversion factor 1000mL = 1L. When 15.0mL is divided by 1000 mL, we obtain a volume of 0.015 L.

Now we can rearrange the equation to solve for the number of moles. We can do this by multiplying by L solution on both sides of the equation. The L solution will cancel out on the right side, leaving the number of moles being equal to the molarity times volume like so:

Moles of solute = (L solution) * (Molarity)

Now we just plug the known values in!

Moles of solute = (0.15 L) (0.110M) = 0.00165 moles