# How many moles of neon (Ne) gas have a volume of of 0.84 and a pressure of of 4.6 atm at 222 K?

## the universal gas constant is 0.0821 $\left(L \cdot a t m\right)$/$\left(m o l \cdot K\right)$

Mar 31, 2017

Approx. $0.2 \cdot m o l$ $\text{of neon gas.}$

#### Explanation:

$n = \frac{P V}{R T} = \frac{4.6 \cdot \cancel{a t m} \times 0.84 \cdot \cancel{L}}{0.0821 \cdot \cancel{L \cdot a t m} \cdot \cancel{{K}^{-} 1} \cdot m o {l}^{-} 1 \times 222 \cdot \cancel{K}}$

=??1/(mol^-1)=1/(1/(mol))=mol as required............

Note that you did not specify the units of volume. I have ASSUMED it was $\text{litres}$.............

The given calculation gives UNITS of moles as required.