How many moles of #NH_3# are produced when 1.2 moles #H_2# reacts?

1 Answer
Mar 16, 2016

Answer:

#N_2(g) + 3H_2(g) rarr 2NH_3(g)#. Approx. #0.8# #mol# ammonia are produced.

Explanation:

We assume (very unreasonably!) quantitative reaction.

The stoichiometry of the reaction dictates that for each equiv dinitrogen, 3 equiv of dihydrogen react, to give 2 equiv ammonia.

Since there are #1.2# #mol# dihydrogen, #0.4# #mol# dinitrogen could have reacted; thus, an #0.8# #mol# quantity of ammonia could have been produced.

All I am doing is following the reaction stoichiometry. Note that such a quantitative reaction in dinitrogen reduction is very unfeasible, and a chemical engineer would jump for joy if such turnovers were achieved.