# How many moles of NH_3 are produced when 1.2 moles H_2 reacts?

Mar 16, 2016

${N}_{2} \left(g\right) + 3 {H}_{2} \left(g\right) \rightarrow 2 N {H}_{3} \left(g\right)$. Approx. $0.8$ $m o l$ ammonia are produced.

#### Explanation:

We assume (very unreasonably!) quantitative reaction.

The stoichiometry of the reaction dictates that for each equiv dinitrogen, 3 equiv of dihydrogen react, to give 2 equiv ammonia.

Since there are $1.2$ $m o l$ dihydrogen, $0.4$ $m o l$ dinitrogen could have reacted; thus, an $0.8$ $m o l$ quantity of ammonia could have been produced.

All I am doing is following the reaction stoichiometry. Note that such a quantitative reaction in dinitrogen reduction is very unfeasible, and a chemical engineer would jump for joy if such turnovers were achieved.