How many moles of nitrogen gas will occupy a volume of 347 mL at 6680 mmHg and 27 #"^o#C?

1 Answer
Nov 29, 2016

Answer:

#6680*mm*Hg# is not a realistic measurement of pressure....

Explanation:

I assume you mean #(6680*mm*Hg)/(760*mm*Hg*atm^-1)=8.79*atm#.

And we use the Ideal Gas Equation:

#n=(PV)/(RT)=(8.79*atmxx0.347*L)/(0.0821*L*atm*K^-1*mol^-1xx300*K)=0.124*mol#

What is the mass of the quantity of nitrogen gas?