# How many moles of nitrogen gas will occupy a volume of 347 mL at 6680 mmHg and 27 "^oC?

Nov 29, 2016

$6680 \cdot m m \cdot H g$ is not a realistic measurement of pressure....

#### Explanation:

I assume you mean $\frac{6680 \cdot m m \cdot H g}{760 \cdot m m \cdot H g \cdot a t {m}^{-} 1} = 8.79 \cdot a t m$.

And we use the Ideal Gas Equation:

$n = \frac{P V}{R T} = \frac{8.79 \cdot a t m \times 0.347 \cdot L}{0.0821 \cdot L \cdot a t m \cdot {K}^{-} 1 \cdot m o {l}^{-} 1 \times 300 \cdot K} = 0.124 \cdot m o l$

What is the mass of the quantity of nitrogen gas?