# How many moles of nitrogen, N, are in 85.0 g of nitrous oxide, N_2O?

Feb 26, 2017

$\text{Approx. 4 moles}$

#### Explanation:

$\text{Moles of nitrous oxide} = \frac{85 \cdot g}{44.01 \cdot g \cdot m o {l}^{-} 1}$

$= 1.93 \cdot m o l$.

Since, clearly, there are $\text{2 moles of nitrogen atoms}$ $\text{per mole of nitrous oxide}$, we simply double the molar quantity of $\text{nitrous oxide:}$

1.93*molxx2*mol*N*mol^-1NO=??mol

Feb 26, 2017