How many moles of nitrogen, N, are in 85.0 g of nitrous oxide, #N_2O#?

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Answer 1 · 2017-02-26T14:57:39

#"Approx. 4 moles"#

#"Moles of nitrous oxide"=(85*g)/(44.01*g*mol^-1)#

#=1.93*mol#.

Since, clearly, there are #"2 moles of nitrogen atoms"# #"per mole of nitrous oxide"#, we simply double the molar quantity of #"nitrous oxide:"#

#1.93*molxx2*mol*N*mol^-1NO=??mol#

Answer 2 · 2017-02-26T15:12:05

3.86 moles of N

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