How many moles of nitrogen, N, are in 85.0 g of nitrous oxide, #N_2O#?

2 Answers
Feb 26, 2017

#"Approx. 4 moles"#

Explanation:

#"Moles of nitrous oxide"=(85*g)/(44.01*g*mol^-1)#

#=1.93*mol#.

Since, clearly, there are #"2 moles of nitrogen atoms"# #"per mole of nitrous oxide"#, we simply double the molar quantity of #"nitrous oxide:"#

#1.93*molxx2*mol*N*mol^-1NO=??mol#

Feb 26, 2017

3.86 moles of N

Explanation:

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