How many moles of #O_2# are required to generate 18 moles of #H_2O# in the reaction #2C_8H_18 + 25O_2 -> 16CO_2 + 18H_2O#?

1 Answer
Apr 12, 2016

Answer:

You will need 25 moles, but this is not based on the equation alone.

Explanation:

#18mol H_2 O x ((25 molO_2)/ (18molH_2 O)) = 25 mol O_2#

Moles of water cancel, leaving you with moles of Oxygen.
Factor out 18/18=1.
25 x 1 = 25